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Wouldn't stiffer springs give you less advance at idle and, hence, more ad=
vance at speed?
=20
Dave=20
=20
=20
-----Original Message-----
From: Peter Arakelian <peterara@msn.com>
To: Tony Drews <tony@tonydrews.com>
Cc: triumphs@autox.team.net <triumphs@autox.team.net>
Sent: Sat, Feb 29, 2020 2:02 pm
Subject: Re: [TR] distributor advance
#yiv4781498517 #yiv4781498517 -- _filtered {} _filtered {} #yiv4781498517 #=
yiv4781498517 p.yiv4781498517MsoNormal, #yiv4781498517 li.yiv4781498517MsoN=
ormal, #yiv4781498517 div.yiv4781498517MsoNormal {margin:0in;margin-bottom:=
.0001pt;font-size:11.0pt;font-family:sans-serif;} #yiv4781498517 a:link, #y=
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erline;} #yiv4781498517 .yiv4781498517MsoChpDefault {} _filtered {} #yiv478=
1498517 div.yiv4781498517WordSection1 {} #yiv4781498517 I should have done =
this from the start.=C2=A0 checked the Bentley manual.=C2=A0 Lists my distr=
ibutor and the advance specs.=C2=A0 Shows centrifugal advance at idle of 0-=
2 degrees on the crank.=C2=A0 So my stiffer springs are advancing too much =
initially, which will reduce the amount of extra advance I get at speed..=
=C2=A0 Will change back. =C2=A0 Sent from Mail for Windows 10 =C2=A0 From:=
Tony Drews
Sent: Saturday, February 29, 2020 10:16 AM
Subject: Re: distributor advance =C2=A0 I'm not saying all advance is used =
at idle, but what I'm saying is that when all the mechanical advance is use=
d, you're at a different advance setting than before (you had to change the=
timing after changing the springs, so when you do that the full advance am=
ount changes correspondingly).=C2=A0 I'm unclear which direction it changed=
.=C2=A0 Your "at 3200 RPM" observation would almost always be at full advan=
ce regardless of which springs you're using.Stiffer springs should equate t=
o less advance at idle than before I'd think.Regards, Tony DrewsOn 2/28/202=
0 8:09 PM, Peter Arakelian wrote:=20
Tony, if I follow you correctly, you are saying that by changing the spring=
s I may have made it so that all=C2=A0the mechanical advance is used up at =
idle and=C2=A0I=C2=A0may have no more at speed.=C2=A0 Where with the older =
springs I would get mechanical advance later in the rpms and so have more a=
dvance at speed. Would the marking on the weight of 13 degrees indicate its=
maxium advance?=C2=A0 If so, I suspect I may in fact be using all the mech=
anical at idle since my idle timing jumped=C2=A0past the pully markings and=
I can only estimate a 10-15 degree jump.=C2=A0Maybe I should go back to th=
e old springs. =C2=A0=20
>>The springs should just change what RPM it takes to get to full advance=
=20
but the full advance should be the same (weights against the stops).?=20
I'm a little unclear on how much you changed the timing, it sounds like=20
you had to retard the timing after the spring replacement - this would=20
also retard the "all in" timing, which would be what you're running at=20
3200 RPM.? It's possible it's worse at 3200 now than it was before=20
because the full advance timing is now less.<< =C2=A0 ** triumphs@autox.te=
am.net **
Archive: http://www.team.net/pipermail/triumphs http://www.team.net/archiv=
e
sey@cs.com
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<div style=3D"color:black;font: 12pt Arial, Helvetica, sans-serif;">
<div> <font size=3D"3">Wouldn't stiffer springs give you less advance at id=
le and, hence, more advance at speed?</font><br>
</div>
<div> <br>
</div>
<div style=3D"clear:both"><font size=3D"4">Dave </font><br>
<br>
</div>
<div> <br>
</div>
<div> <br>
</div>
<div style=3D"font-family:arial,helvetica;font-size:10pt;color:black">-----=
Original Message-----<br>
From: Peter Arakelian <peterara@msn.com><br>
To: Tony Drews <tony@tonydrews.com><br>
Cc: triumphs@autox.team.net <triumphs@autox.team.net><br>
Sent: Sat, Feb 29, 2020 2:02 pm<br>
Subject: Re: [TR] distributor advance<br>
<br>
<div id=3D"yiv4781498517"><style>#yiv4781498517 #yiv4781498517 -- _filte=
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8517MsoChpDefault {} _filtered {} #yiv4781498517 div.yiv4781498517WordSec=
tion1 {} #yiv4781498517 </style>
<div>
<div class=3D"yiv4781498517WordSection1">
<div class=3D"yiv4781498517MsoNormal">I should have done this from the star=
t. checked the Bentley manual. Lists my distributor and the adv=
ance specs. Shows centrifugal advance at idle of 0-2 degrees on the c=
rank. So my stiffer springs are advancing too much initially, which
will reduce the amount of extra advance I get at speed.. Will change=
back.</div>
<div class=3D"yiv4781498517MsoNormal"> </div>
=20
<div class=3D"yiv4781498517MsoNormal">Sent from <a rel=3D"noopener noreferr=
er" shape=3D"rect" target=3D"_blank" removedlink__e725e969-990d-4404-b8c0-b=
2ba8104fa0b__href=3D"https://go.microsoft.com/fwlink/?LinkId=3D550986";>
Mail</a> for Windows 10</div>
=20
<div class=3D"yiv4781498517MsoNormal"> </div>
=20
<div class=3D"yiv4781498517yqt0093552242" id=3D"yiv4781498517yqt70187">
<div style=3D"border:none;border-top:solid #E1E1E1 1.0pt;padding:3.0pt 0in =
0in 0in;">
<div class=3D"yiv4781498517MsoNormal" style=3D"border:none;padding:0in;"><b=
>From: </b><a rel=3D"noopener noreferrer" shape=3D"rect" ymailto=3D"mailto:=
tony@tonydrews.com" target=3D"_blank" removedlink__e725e969-990d-4404-b8c0-=
b2ba8104fa0b__href=3D"mailto:tony@tonydrews.com";>Tony Drews</a><br clear=3D=
"none">
<b>Sent: </b>Saturday, February 29, 2020 10:16 AM<br clear=3D"none">
<b>Subject: </b>Re: distributor advance</div>
</div>
<div class=3D"yiv4781498517MsoNormal"> </div>
=20
<div>I'm not saying all advance is used at idle, but what I'm saying is tha=
t when all the mechanical advance is used, you're at a different advance se=
tting than before (you had to change the timing after changing the springs,=
so when you do that the full advance
amount changes correspondingly). I'm unclear which direction it chan=
ged. Your "at 3200 RPM" observation would almost always be at full ad=
vance regardless of which springs you're using.</div>
<div>Stiffer springs should equate to less advance at idle than before I'd =
think.</div>
<div>Regards, Tony Drews</div>
<div>
<div class=3D"yiv4781498517MsoNormal">On 2/28/2020 8:09 PM, Peter Arakelian=
wrote:</div>
=20
</div>
<blockquote style=3D"margin-top:5.0pt;margin-bottom:5.0pt;">
<div>
<div class=3D"yiv4781498517MsoNormal">Tony, if I follow you correctly, you =
are saying that by changing the springs I may have made it so that all =
;the mechanical advance is used up at idle and I may have no more=
at speed. Where with the older springs I would get mechanical
advance later in the rpms and so have more advance at speed.</div>
=20
</div>
<div>
<div class=3D"yiv4781498517MsoNormal">Would the marking on the weight of 13=
degrees indicate its maxium advance? If so, I suspect I may in fact =
be using all the mechanical at idle since my idle timing jumped past t=
he pully markings and I can only estimate a 10-15 degree jump. Maybe
I should go back to the old springs.</div>
=20
</div>
<div>
<div class=3D"yiv4781498517MsoNormal"> </div>
=20
</div>
</blockquote>
<div class=3D"yiv4781498517MsoNormal" style=3D"margin-right:.5in;margin-bot=
tom:5.0pt;margin-left:.5in;">
>>The springs should just change what RPM it takes to get to full adv=
ance <br clear=3D"none">
but the full advance should be the same (weights against the stops).? <br c=
lear=3D"none">
I'm a little unclear on how much you changed the timing, it sounds like <br=
clear=3D"none">
you had to retard the timing after the spring replacement - this would <br =
clear=3D"none">
also retard the "all in" timing, which would be what you're running at <br =
clear=3D"none">
3200 RPM.? It's possible it's worse at 3200 now than it was before <br clea=
r=3D"none">
because the full advance timing is now less.<<</div>
</div>
=20
<div class=3D"yiv4781498517MsoNormal"> </div>
=20
</div>
</div>
</div>
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