>Where Dan is wrong though, is that the V8 does provide you with extra power
>and torque and you will then reach said speed more quickly than in a stock
>powered car. The quickness is related to acceleration and the quicker you
>able to accelerate the more force your car is carrying and the more braking
>force is required to stop it. This is where Dan is mistaken.
Oh? Given a constant braking power, your stopping time & distance is a
function of Velocity when brakes are applied and Mass. If your mass
stays the same in an engine swap you will stop just as quickly from the
same Velocity as you did before.
How quickly you reach a given velocity is not part of the equation.
> the quicker you
>able to accelerate the more force your car is carrying
Nope. It is a factor of mass and velocity when the brakes are applied.
Rate of acceleration has nothing to do with rate of deceleration,
assuming the accelerating power is not active during deceleration. If
you have one foot pressing down on the accelerator pedal and the other
foot pressing down on the brakes all bets are off.
Your Chevy II with a four cylinder engine hitting a brick wall at 60 MPH
will get the same damage as a Chevy II with the 396 SS option hitting a
brick wall at 60 MPH. This assumes they both weigh the same.
TeriAnn Wakeman Marigold Ltd.
Santa Cruz, California Web design, site updating, testing
webmaster@overlander.net search engine optimization, graphics
and more
http://www.overlander.net/Marigold/index.html
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