>Jon,
> Maybe I am wrong but wouldn't the following line be different.
>Patomoshpere * Vatmoshpere = Psystem * Vsystem
> 1 atm * 23 in^3 = 7.85 atm * Vsystem
> Vsystem = approx 3 in^3 : this is the volume of air the cylinder
>volume
>Vsystem
>would be 23 in^3 and Vatmosphere would be 180.55???? (Not 3). That might
>throw
>a wrench into the plan.
> Anyone??
your 100% right. I did the calculations backward and the long way its
much simpler than I made it out to be. But I believe the original was
still correct. I realized this shortly after I posted it.
1 atm = 14.7 (thanks for the correction Kim)
diameter of cyl = 1.5" (are these correct? anybody)
throw of cyl = 13"
:still neglecting
temp variation
Patomoshpere * Vatmoshpere = Psystem * Vsystem
14.7 psi * Vatm = (110 psi+ 14.7) * 22.97 in^3 :110 is gauge
pressure
:we need
absolute pressure Vatmosphere = 172.88 in^3
20 ft^3 = 34560 in^3 / 172.88 in^3 = precisely 199.9 door openings
(weird after making corrections an not rounding its virtually the same
result)
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