Mail Archive Search: <+subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*CB\/SW\s*$/>

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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*CB\/SW\s*$/: 4 ]

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1. CB/SW (score: 1): Author: "James Lea" <clocks@midcoast.com>; Date: Mon, 19 Apr 2004 14:46:24 -0400; At one time I knew the answer to this question but my brain seems to be forgetting more and more lately so here is an easy one. A stock coil says CB (contact breaker) on one side and SW (switch ) on; /html/healeys/2004-04/msg00590.html (6,627 bytes)
2. Re: CB/SW (score: 1): Author: "Classic-Car-World Ltd" <enquiries@classic-car-world.co.uk>; Date: Mon, 19 Apr 2004 22:13:43 +0100; Hi James, I would suggest that if your healey is still positive ground then the CB equates to +ve and the SW is -ve. If the car has been converted to negative ground then the connections are reversed; /html/healeys/2004-04/msg00597.html (7,691 bytes)
3. Re: CB/SW (score: 1): Author: Dave & Marlene <rusd@velocitus.net>; Date: Mon, 19 Apr 2004 15:16:15 -0600; If the coil was originally from a positive ground car, CB would be +. The CB (contact breaker) is the points making a connection to ground which is positive. The SW (ignition switch) lead would be -; /html/healeys/2004-04/msg00598.html (7,532 bytes)
4. Re: CB/SW (score: 1): Author: "James Lea" <clocks@midcoast.com>; Date: Mon, 19 Apr 2004 17:37:02 -0400; I just finished converting to negative ground as part of the electrics redo. I plugged in the wire from the distributor to the - side of the coil and it seems to work fine. Also put in a geared start; /html/healeys/2004-04/msg00600.html (6,714 bytes)

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