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1. A question -- if two Bricklins... (score: 1): Author: "K M" <symbiotic@hotmail.com>; Date: Thu, 09 Mar 2000 23:10:19 PST; Fill in please. If two Bricklins, each going 60 mph, have a head-on collision, that is like one Bricklin running into a brick wall at (how many mph)? Thanks, it will settle a debate, and it doesn't h; /html/bricklin/2000-03/msg00061.html (7,525 bytes)
2. Re: A question -- if two Bricklins... (score: 1): Author: Steve Bepko <sbepko@bcpl.net>; Date: Fri, 10 Mar 2000 09:00:01 -0500 (EST); Let's assume that (a) the amount of damage caused to a car is directly proportional to the amount of energy it absorbed, and (b) what you want to know is how fast the single Bricklin must be going wh; /html/bricklin/2000-03/msg00062.html (10,230 bytes)
3. Re: A question -- if two Bricklins... (score: 1): Author: Jonathan Garruba <jgarru01@longisland.poly.edu>; Date: Fri, 10 Mar 2000 12:56:27 -0500; the two cars are approaching each other at 120 mph. If both cars are exactly the same weight their velocity is 0mph after the crash. So if one car is traveling at 120mph and hits a wall and after the; /html/bricklin/2000-03/msg00063.html (7,957 bytes)
4. Re: A question -- if two Bricklins... (score: 1): Author: "K M" <symbiotic@hotmail.com>; Date: Fri, 17 Mar 2000 10:51:44 PST; Steve, I am a bit brain dead but are you saying that the force of two cars hitting headon at 60 mph would be the same as one car going 60 hitting an immovable wall. That is my understanding of the p; /html/bricklin/2000-03/msg00107.html (11,351 bytes)
5. Re: A question -- if two Bricklins... (score: 1): Author: Steve Bepko <sbepko@bcpl.net>; Date: Fri, 17 Mar 2000 15:34:12 -0500 (EST); == "Force" isn't really the operational concept here. If the wall isn't "hurt" by the collision, then the only other place for the energy to go (assuming - and it's a big assumption - that the car do; /html/bricklin/2000-03/msg00108.html (13,139 bytes)
6. Re: A question -- if two Bricklins... (score: 1): Author: GLCurley@aol.com; Date: Fri, 17 Mar 2000 15:43:49 EST; So in summary if one is driving a Bricklin 60 mph and has a choice between hitting a brick wall head on and a Yugo (loaded to Bricklin weight equivalent) coming in the opposite direction at 60 mph, o; /html/bricklin/2000-03/msg00109.html (7,454 bytes)
7. Re: A question -- if two Bricklins... (score: 1): Author: "K M" <symbiotic@hotmail.com>; Date: Fri, 17 Mar 2000 13:10:53 PST; It is my understanding that both options would be identical, assuming that you are not taking into account the different engineering of the cars. On the other hand, it would be better but embarrassin; /html/bricklin/2000-03/msg00110.html (8,332 bytes)
8. Re: A question -- if two Bricklins... (score: 1): Author: Steve Bepko <sbepko@bcpl.net>; Date: Fri, 17 Mar 2000 17:24:46 -0500 (EST); == Sort of, but not for the reason you think. If it was another Bricklin, then it wouldn't matter, unless of course you are altruistic and figure 1 less Bricklin in the world is better than 2 less. B; /html/bricklin/2000-03/msg00111.html (9,456 bytes)
9. Re: A question -- if two Bricklins... (score: 1): Author: GLCurley@aol.com; Date: Fri, 17 Mar 2000 18:44:30 EST; No, I was accounting for the Yugo being more deformable, definitely not two Bricklins (that is too painful of a thought). Then if we assume that the Yugo absorbs 70% and the Brick 30%, part of that 3; /html/bricklin/2000-03/msg00112.html (8,180 bytes)

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