In a message dated 2/2/99 11:15:01 PM Eastern Standard Time,
jamesbrt@mindspring.com writes:
> Will I require 2X the peddle pressure or the same peddle
> pressure as the original Tiger, given the same braking quantity?
>
> Consider:
> The Tiger master cylinder pushed on 4 wheel cylinders with
> one piston.
> The new master cylinder will push on 2 wheel cylinders with
> each piston.
>
> The dual cylinder is inline.
Jim,
My guess is the same pedal pressure.
Originally you have force of breaking 4 equal brake cylinders = hydraulic
pressure X master cylinder cross sectional area.
New system has two piston with same bore, so the total force of braking =
force braking 2 equal brake cylinders (hydraulic pressure X master cylinder
cross section area) + force braking 2 equal brake cylinders (hydraulic
pressure X master cylinder cross section area) = the same total force. I
know, this isn't standard mathematical notation, but what the heck. Each
piston in the dual master cylinder is pushing half as hard, but the total
force applied to the inline plunger is the same as originally.
If the rerouted lines are considerably different, there could be other losses,
but those are probably negligible. Assuming the brake pedal lever arm remains
the same.
Regards,
Rob Kempinski
Melbourne Fl
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