Now where is Larry our Mathematician when you need him.... Case you folks
don't know.... Larry Mayfield "Mayf" is a real life Rocket Scientist.... He
doesn't live in Huntsville Alabama because that was the only place they
would let him Park his Mobile home.... Kvack.... seriously Watch what
Larry does with this.... He is building a DB/MS out of a Sunbeam.... and I
have been monitoring his Progress on my occasional trips to Huntsville ...
nice guy and he has a real nice mobile home... (two story brick exclusive
neighborhood and so on) Super wife and so on...
Larry has never run the salt... but like most of us.... he has always
wanted to ... and as for my Turbo efforts.... Well it was Mayf that got me
going down this road with his Logic and understanding of the systems...
that and his ability to explain it in words I could understand.....
Keith
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> From: Beth Butters <bbutters@dmi.net>
> To: land-speed@autox.team.net
> Subject: Cooling
> Date: Monday, November 15, 1999 10:33 PM
>
>
> I have finally found the information I needed to make an
>attempt at
calculateing how much water I need to properly cool my motor. The latest
edition of Circle Track has the best of S. Yunick which answered a
question on cooling which got me going on this. So here goes. Given::: 1
BTU is the amount of heat required to raise 1# of water 1 degree F. 1
gal. Of gasoline weighs 6.5#s. 1 gal. Of water weighs 8.33#s. It takes
1/2 # of fuel/ H.P./hour. 1/4 to 1/3 of the Btus released durring
combustion are disipated thew the radiator or thew radiation. There are
19,383 BTUs/# in the blue Erc A -8B 118 octane racing fuel or 127,940
BTUs/gal. So, for every gallon burned you need
127,940BTUx.3=38,382BTUs of cooling or 5814 BTUs /# . 800H.P. requires
800H.P.x1/2#fuel/hr.=400#fuel/hr or 6.66#/min or .111#/sec. It takes
approx. 110 sec to run threw the 5 mile at 220mph, full throttle from the 2
mile on, so this is where you are really using the 800H.P. I try to correc!
> t for this later on. 110 sec. Run X .111 #fuel/sec. = 12.21# of
gasoline. You may use more than this because of running rich but I assume
this is all the motor really uses to produce the power??????? Soooooo.
12.21#s of fuelx19683BTUs/# =240,329BTUs X.3 (the amount released into the
cooling system) = 72,099BTUs that you need to cool with water. Now 1 gal.
of water wieghs 8.33 #s if it is iced to 40 deg. And allowed to raise to
220 deg. There is a change of l80 degrees which would require
180X8.33=1500 BTUs per gal. to raise it that l80 deg. So how much of a heat
> sink (tank gallons) do we need.?? If the water was required to cool the
entire 72,099BTUs we have Calculated we need to deal with ( please
disregard the blue and underline I really don"t have a clue how to run
this thing) 72,099 BTUs devided by 1500 BTUs=48gal. of water required.
If we assume the first mile which takes approx. 36 sec to run (100mph.
Avg.) the heat produced is used to heat up the block and bring everything
up to operating temp. then we can changfe our calculation to a 75 sec run
needing cooling. Therefor 75secsX.111#/sec=8.3# of fuel l9683BTUs/# X.3=
49,158 BTUs devided by 1500 BTUs / gal. water= 32.77gal. required . How
much for you car??? 32.77gal. devided by 800H.P. = .041 gal./H.P. or 4.125
gal/ 100 H.P. I know this is more than most guys use , but I can't
convince myself it's not what I need, Ive got a 40 gal. tank I'm mounting
behind my seat in the Salt Hawk. L.Kvach Butters ending my longest typeing
exersize in 30 years,..--------!
> --
>
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