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Re: [Healeys] Hot & Cold Brake Wires

To: Michael Salter <michaelsalter@gmail.com>
Subject: Re: [Healeys] Hot & Cold Brake Wires
From: "R. Lindsay via Healeys" <healeys@autox.team.net>
Date: Sun, 11 Jul 2021 18:38:11 -0400
Cc: Healey List <healeys@autox.team.net>
Delivered-to: mharc@autox.team.net
Delivered-to: healeys@autox.team.net
References: <CAB3i7LLP=_5XemHWP6KYD-yB5pGS+3a-PasK3u+c_2K9xk2Y-w@mail.gmail.com>
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Thanks Michael.=20

Price Lindsay

Cell: 630-841-6300
Email: 050.rpl@gmail.com

Sent from my iPhone

> On Jul 11, 2021, at 4:41 PM, Michael Salter <michaelsalter@gmail.com> wrot=
e:
>=20
> =EF=BB=BF
> You are correct.  The live side is the solid green. Live with ignition on.=

>=20
> M
>=20
>> On Sun., Jul. 11, 2021, 4:22 p.m. R. Lindsay via Healeys, <healeys@autox.=
team.net> wrote:
>> Is there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the wi=
ring of the brake switch in a 67 BJ8.  I can see there are two wires to the s=
witch, Green and Green/Purple.  I presume the current enters the switch off o=
f one wire and leaves the switch off the other.  I would guess the current c=
omes to the switch from the green wire and exits via the green/purple, but i=
ts only a guess.  Further the =E2=80=9Chot=E2=80=9D side, I=E2=80=99d guess,=
 is the one that takes the current to the switch (green.)
>>=20
>> Is my thinking correct, wrong or neither, i.e., there is no hot or cold s=
ide.  Thank you for your input.=20
>>=20
>> Price Lindsay
>>=20
>> Sent from my iPad
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>>=20
>> Unsubscribe/Manage: http://autox.team.net/mailman/options/healeys/michael=
salter@gmail.com
>>=20

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<html><head><meta http-equiv=3D"content-type" content=3D"text/html; charset=3D=
utf-8"></head><body dir=3D"auto">Thanks Michael.&nbsp;<br><br><div dir=3D"lt=
r">Price Lindsay<div><br></div><div>Cell: 630-841-6300</div><div>Email: 050.=
rpl@gmail.com</div><div><br></div><div>Sent from my iPhone</div></div><div d=
ir=3D"ltr"><br><blockquote type=3D"cite">On Jul 11, 2021, at 4:41 PM, Michae=
l Salter &lt;michaelsalter@gmail.com&gt; wrote:<br><br></blockquote></div><b=
lockquote type=3D"cite"><div dir=3D"ltr">=EF=BB=BF<div dir=3D"auto">You are c=
orrect.&nbsp; The live side is the solid green. Live with ignition on.<div d=
ir=3D"auto"><br></div><div dir=3D"auto">M</div></div><br><div class=3D"gmail=
_quote"><div dir=3D"ltr" class=3D"gmail_attr">On Sun., Jul. 11, 2021, 4:22 p=
.m. R. Lindsay via Healeys, &lt;<a href=3D"mailto:healeys@autox.team.net";>he=
aleys@autox.team.net</a>&gt; wrote:<br></div><blockquote class=3D"gmail_quot=
e" style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">I=
s there a =E2=80=9Chot=E2=80=9D or =E2=80=9Ccold=E2=80=9D side to the wiring=
 of the brake switch in a 67 BJ8.&nbsp; I can see there are two wires to the=
 switch, Green and Green/Purple.&nbsp; I presume the current enters the swit=
ch off of one wire and leaves the switch off the other.&nbsp; I would guess t=
he current comes to the switch from the green wire and exits via the green/p=
urple, but its only a guess.&nbsp; Further the =E2=80=9Chot=E2=80=9D side, I=
=E2=80=99d guess, is the one that takes the current to the switch (green.)<b=
r>
<br>
Is my thinking correct, wrong or neither, i.e., there is no hot or cold side=
.&nbsp; Thank you for your input. <br>
<br>
Price Lindsay<br>
<br>
Sent from my iPad<br>
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