This: "This would be indicated by a dead short between the input post and the
ground post with the points open. "
Should read: "This would be indicated by a dead short between the points base
and the ground post with the points open. "
Bob
On 12/30/2012 7:38 AM, Bob Spidell wrote:
> The pump circuit is fairly simple: it's a solenoid (electromagnet,
> essentially) in series with a switch (the points).
> The power source connects to one solenoid lead at the long brass screw, which
> should be otherwise isolated. The other
> solenoid lead connects to the base of the points, where the points 'blade' is
> attached. The unshielded copper lead
> from the points connects under the pedestal hold-down screw opposite the side
> with the input brass screw. The transil
> should connect between the points base and the same pedestal screw the wire
> from the points connect to.
>
> When the points are closed the whole circuit will have near-zero impedance
> for a split second then impedance will
> build as the solenoid coil gets saturated. With the points open, there
> should be continuity between the input post
> and the points base only (there should always be continuity from the points
> on the armature to ground).
>
> There is some polarity issue with the solenoid leads, but it will operate
> with the leads reversed. If your pump
> hasn't previously been assaulted the small terminals fit properly only one
> way (sometimes, the leads are red/black,
> but I've only seen black/black).
>
> Did you get a bidirectional transil (like the kit I recommended)? If so, the
> orientation of the transil doesn't
> matter. If not, you could have the transil connected backwards. This would
> be indicated by a dead short between the
> input post and the ground post with the points open.
>
> Bob
>
>
--
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Bob Spidell San Jose, CA bspidell@comcast.net
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