To: | Geo Hahn <geohahn@azstarnet.com> |
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Subject: | Re: 76 tr6 compression |
From: | Dave Massey <105671.471@compuserve.com> |
Date: | Wed, 23 Feb 2000 11:13:18 -0500 |
Cc: | TR List <triumphs@autox.team.net> charset=ISO-8859-1 |
Geo writes: >Can it be as easy as multiplying atmospheric pressure (14.7 psi) times >compression ratio? For 7.75 that would be 114 psi. That sounds low but so >does 7.75. > >I assume that whatever the formula is it will vary based on your altitude. > >Geo Hahn George, There's another fly in the ointment and that is the issue of gauge pressure vs absolute pressure. What you say is true about atmospheric pressure being 14.7 PSI (14.696 actually but who's counting) but the gauge reads in gauge pressure which is short hand for the difference between abient (atmospheric) pressure and process pressure and the gauge reads zero at atmospheric pressure. If you take 14.7 PSI times 7.75 and get 114 PSI this is the absolute pressure but your gauge will read 14.7 PSI - less or 99.3 PSI. Actual readings are quite a bit higher and the only really plausable explaination to me is the heating effect that occures when air is compressed. Dave |
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