triumphs
[Top] [All Lists]

RE: Electric Waterpumps

To: "'Michael Marr'" <mmarr@idcnet.com>, Triumphs List <triumphs@autox.team.net>
Subject: RE: Electric Waterpumps
From: Randall Young <randallyoung@earthlink.net>
Date: Thu, 18 Mar 1999 10:49:59 -0800
Organization: Navcom Technology, Inc
So, another way to look at this is :

>From the same factory chart, full power at 1250 rpm is about 24hp = about 
12 lb/hr fuel.
If 1/3 of the input heats the water, then using your equation, with a 2 ft 
head and 20 deg rise gives us .0067 hp for the pump.
Then, using the cube law, a 4 times increase in pump speed takes a 64 times 
increase in power, for .43 hp at 5000 rpm.  7000 rpm takes 175 times as 
much, or over 1 hp.

Still not a lot, but noticeably higher.

Of course, for any of this have any meaning, we have to assume that someone 
actually engineered the water pump, instead of just building something and 
finding that it worked "good enuf".  Considering that the 4cyl TR engine 
was originally a tractor engine that produced maybe 45hp at the flywheel, 
and AFAIK the water pump is still the same, I'm not sure that's a good 
assumption <g>

Randall


On Wednesday, March 17, 1999 6:35 PM, Michael Marr [SMTP:mmarr@idcnet.com] 
wrote:
> For centrifugal pumps, flow is directly proportional to speed and power
> increases as the cube of the speed.  Thus, if a pump runs at twice its
> normal speed it consumes eight times the power.
>
> At idle, the engine is producing minimum BHP, therefore the rejected heat
> will also be less, although probably a greater percentage of the input
> energy than at full load.
> -----Original Message-----
> From: Randall Young <randallyoung@earthlink.net>
> To: 'Michael Marr' <mmarr@idcnet.com>
> Cc: Triumphs (E-mail) <triumphs@autox.team.net>
> Date: Wednesday, March 17, 1999 7:20 PM
> Subject: RE: Electric Waterpumps
>
>
> >Nice analysis !
> >
> >One quibble : your illustration is for minimum flow to keep the engine 
cool
> >at full output.
> >Now, we need the flow required at idle to size the pump (which I suspect 
is
> >worst case, but I'm not certain), then the power vs rpm curve for a
> >centrifugal water pump extrapolated to redline (or maybe a little beyond
> >for us "boy racer" types) <g>
> >
> >I suspect the pump on your Audi was required to cool the turbocharger
> >housing after shutdown.  One of the bugaboos of turbos on production 
cars
> >is that if they are shut off suddenly after high load operation, the
> >exhaust heat will cook the oil in the turbo bearings, leading to coke
> >formation and failure.  AFAIK, this is the main reason to run water 
through
> >the turbo housing in the first place.
> >
> >Was the electric water pump the only one ?  or did it have a separate, 
belt
> >driven pump ?
> >
> >Randall
> >
> >On Wednesday, March 17, 1999 4:12 PM, Michael Marr 
[SMTP:mmarr@idcnet.com]
> >wrote:
> >>
> >> Seems to me that my 1989 Audi 200 Turbo (God, I loved that car...) had 
an
> >> electrically driven water pump for the purpose of maintaining flow
> >through
> >> the block after shutdown.
> >>
> >> As for power consumed, the equation is:
> >>
> >> Horsepower = (TDH X Flow)/(3960 X Pump Efficiency)
> >>
> >> where TDH is the total discharge head (in feet) and the flow is mea  
sured
> >in
> >> gpm.  Required flow rate at full engine load (max heat rejection) can 
be
> >> calculated from:
> >>
> >> Heat rejected = mass flow X specific heat X temperature rise
> >>
> >> where specific heat = 1, for water.  The temperature rise is the
> >temperature
> >> difference between the cooled water supplied to the block and the 
heated
> >> water leaving the block.  Thus, FOR THE SAKE OF ILLUSTRATION 
ONLY(!!!),
> >> let's assume that an engine discharges heat from the block equivalent 
to
> >33%
> >> of it's energy input, and that the engine is 33% efficient.  Thus, for 
a
> >100
> >> BHP engine operating at full output, the heat equivalent of 100 BHP is
> >> rejected to the cooling system.  This is equivalent to approximately
> >254,600
> >> BTU/Hr.  If we assume a 20 degree temperature difference across the
> >block,
> >> then a water mass flow of about 12,700 lbs/hr, or a little over 25 
gpm,
> >is
> >> required.  If we assume that the pressure drop through the cooling 
system
> >is
> >> around 5 psig, or 11.5 ft head, and we'll assume a pump efficency of 
65%,
> >> then the power consumed by the pump is around 0.11 BHP.  Not much, eh?
> >>
> >> As a sanity check for this calculation, I looked in my TR2 and 3 
factory
> >> manual and found an interesting graph that showed that the engine
> >consumed a
> >> constant 0.5 (imperial) pints/BHP/hour of fuel at full load.  This is
> >> equivalent to about 1,000,000 BTUH input, assuming fuel at 20,000 
BTU/lb,
> >> which means the engine is somewhere between 25 and 30% efficient. 
 This
> >will
> >> change the heat rejected to the cooling jacket, but I can't see the 
water
> >> pump consuming much more than .5 BHP, in a TR3.  OK, I'm ready for the
> >> responses...
> >>
> >> -----Original Message-----
> >> From: Dave Massey <105671.471@compuserve.com>
> >> To: TR List <triumphs@autox.team.net>
> >> Date: Wednesday, March 17, 1999 10:19 AM
> >> Subject: Electric Waterpumps
> >>
> >>
> >> >
> >> >All this talk about electric water pumps raises a few questions:
> >> >1) If the pump and drive pulleys are sized for adequate coolant flow
> >> >at idle will the pump caviate at red-line?
>
> > >2) How much power does the pump use?
> >> >
> >> >The Pump question is much like the fan question with the exception 
that
> >> >there is no induced coolant flow form the forward movement of the
> >vehicle
> >> >as there is with the air.  So if the pump were driven from an 
electric
> >> >motor
> >> >what speed would be used?
> >> >
> >> >The Ideal setup would be to use a variable speed electric drive using
> >> >coolant temperature to determine the pump speed.
> >> >
> >> >On start-up a cold engine requires no pump at all.  As the engine 
begins
> >to
> >> >
> >> >warm up the pump would be required to allow the heater to work.  Once
> >> >warmed up, the engine would need a modest amount of coolant flow at
> >idle.
> >> >At speed, underload the coolant flow requirements would increase but
> >> >not as a function of speed of the engine but as a function of the 
load
> >and
> >> >the heat generated.
> >> >
> >> >I could design such a system for, oh, about $10,000 complete with
> >working
> >> >prototype. ;-)
> >> >
> >> >Talk about gilding the lilly.  Or is it Rube Goldgerg?
> >> >
> >> >Seriously, though, one advantage to an electric driven pump is that 
it
> >can
> >> >continue to run after the engine is shut off and cool down the motor
> >> >between
> >> >runs (eg:at an autocross) a la John Lye.
> >> >
> >> >Dave Massey
> >> >St. Louis MO USA
> >>
> 

<Prev in Thread] Current Thread [Next in Thread>