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Re: [Spridgets] No real difference in tires

To: Frank Clarici <spritenut@comcast.net>,spridgets@autox.team.net
Subject: Re: [Spridgets] No real difference in tires
From: "Timothy H. Collins" <thcollin@mtu.edu>
Date: Wed, 09 Jan 2008 22:36:27 -0500
Looks correct. Works like this.

Tire width times the aspect ratio divided by 25.4 (to convert to 
inches) = the sidewall dimension in inches.
So.... 175 * .7 / 25.4 = 4.82 inches.
Or the sidewall height is 70% (or 80%, the number after the / in the 
tire size) of the tread width.


At 10:16 PM 1/9/2008, you wrote:
>Specification  Sidewall  Radius  Diameter  Circumference  Revs/Mile
>
>155/80-13      4.9in     11.4in    22.8in   71.5in        886
>175/70-13      4.8in     11.3in    22.6in   71.1in        891

Tim Collins
http://www.flickr.com/photos/12702006@N07/ 
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