I believe I have a solution that would be easier to implement. It involves
using a 12v normally closed (NC) relay and a 12v normally open, time delay
relay (NOTD). The coils on both relays are powered by the ignition. To
supply the power for the load connect the source to one of the contacts on
the 12v NC relay and the other contact to one of the contacts on the 12v
NOTD relay. Connect the load to the other contact on the 12v NOTD.
When the ignition is turned on the power will be supplied because the 12v NC
relay close right away and the 12v NOTD will be closed until the time delay
is reached. When the time delay is reached the 12v NOTD will open, stopping
current from flowing to the load.
If needed I could draw the circuit and email it to you.
Please note: I am not an electrical engineer, use at your own risk. 'Nuf
Said.
Paul Cartwright
> >I need help figuring out what parts I need to do this:
> >- initially pass current (12v, <20amps)
> >- stop the flow of current after 5-10 seconds
> >- preferably not flow again until power is turned off and back on
> >(staying off for 5-10 seconds would be okay).
> >
> >I'm thinking of a slow, silent turn signal flasher (but preferably one
> >that would only flash once without a reset).
> >
> >Easy to do, hard to do? What parts do I need and how must they be
> >arranged?
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