Subject: | [Shop-talk] technical question about force applied to mount |
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From: | fishplate at gmail.com (Jeff Scarbrough) |
Date: | Thu, 10 Feb 2011 21:53:39 -0500 |
References: | <OFF90A6187.6DD44618-ON85257834.0008699C-85257834.000B718F@mail.megageek.com> |
On Thu, Feb 10, 2011 at 8:45 PM, <eric at megageek.com> wrote: > I have this tire changer... > > <http://www.harborfreight.com/portable-tire-changer-34542.html > > My question is, what kind of force is put on the base of that tire > changer? If I understand how it works, most of the force will be torque as you pry the bead off the rim. Breaking the bead is toward the ground, and shouldn't be much of a problem. So, take the force times the length of the handle, and divide by the length of the mounting arm. That's what you'll need to provide for in your mount. A lot depends on how hard your tires are to get on and off the rim. Does that help at all? Jeff Scarbrough Corrosion Acres, Ga. |
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