Anyone out there have a tractor and chain I can borrow to pull ......
-----Original Message-----
From: Keith [mailto:kvdurand@mail.esc4.com]
Sent: Wednesday, December 22, 1999 1:54 PM
Cc: oletrucks@autox.team.net
Subject: Re: [oletrucks] Voltage reducer
> Your math is off a bit Bill
Bill knows his math.
> Power(in Watts) = Current X Voltage giving a
> maximum power dissipation across the one Ohm
> resistor of 12 Watts.
NOPE.
P is the variable we are looking for
I (current, is a max of 12)
E (voltage, is also a max of 12)
So, P=12*12
P=144 watts
Or, use the equation that Bill used, P=I^2*R
P=12^2*1, or 144 watts
It was a simple mistake, I believe you put in resistance where there should
have been voltage or amps.
These values are nowhere close to what the motor actually draws throught the
resistor, but using these numbers yields 144 watts, not 12. The only sure
way to figure out what he has is to measure the voltage drop:
> If Sam has access to a voltmeter he could measure
> the voltage drop across the resistor and across
> the fan motor with the fan running in "high" speed.
> The drop should be 6 volts across each is the
> resistor is the proper size.
or measure the amps. Someone mentioned clamp on ammeter, I thought these
only worked with AC. If there are some that work with DC, let me know. I
would like to get one.
oletrucks is devoted to Chevy and GM trucks built between 1941 and 1959
oletrucks is devoted to Chevy and GM trucks built between 1941 and 1959
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