I guess I am not following you at all.
If you jack up the car via the differential, the springs are loaded just the
same as if the car is sitting on the ground; i.e. 50% of the weight is on
the rear springs.
You seem to have skipped a step in your description, perhaps between #2 and
#2 (yes, you have two #2's).
on 1/14/03 1:57 PM, Tim Holt at holtt@nacse.org wrote:
> I'm about to replace the rear springs on my Midget. Got a new set from
> Moss Motors just yesterday. One of the current springs has a cracked
> leaf, plus I have a hunch that the two in there now aren't matched as well.
>
> Anyway, I'm trying to get my mind around how the replacement will go
> (remove old, put in new). Specifically the part about getting the load
> off the springs for removal. Here's how I'm guessing I'll do it (based
> on reading, long walks in the park thinking, etc.)
>
> 1) Jack up rear of car w/lift under rear differential until wheels are
> off ground.
> 2) Remove wheels. At this point the springs are sort of "reverse"
> loaded - instead of the axles pushing up on the springs, they are now
> 'hanging off' the springs.
>
> 2) Put a jack stand under the two axles.
>
> 3) Lower the car just a bit until the springs aren't loaded. Too low
> and the weight of the car is compressing them down. Too high and the
> weight of the axles+wheels is pulling them out.
>
> 4) Remove springs now that they are not under any load, and then replace.
>
> That sound about right?
>
> Tim Holt
> '74 MG Midget
>
--
Max Heim
'66 MGB GHN3L76149
If you're near Mountain View, CA,
it's the primer red one with chrome wires
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