Okay so I was playing a bit fast and lose. :-) Seems most got my point however.
At least I know you guys do read my posts. :-)
Gary McCormick wrote:
>
> I think what Marc /meant/ to say was KE = 1/2 (Iw^2), where KE is the
>kinetic energy of
> the rotating mass, I is the moment of inertia and w is the angular velocity
>(^2 means
> squared).
>
> What this equation tells us is that increasing either the moment of inertia
>of the
> flywheel or it's angular velocity (rpm) will increase the amount of stored
>energy it
> represents. One can also see that it takes more energy input to raise the
>angular
> velocity to a given value if the value of I is higher. I is representative
>of not only
> the mass, but its distribution, and as Marc stated in the full text of his
>post, mass that
> is located further from the rotational center of the flywheel resists
>rotation more than
> the same mass closer to the center (or words to that effect), in addition to
>the thermal
> issues to be considered.
>
> Isn't physic fun?
>
> Gary McCormick
> San Jose, CA
>
> Marc Sayer wrote:
>
> > <snip>The energy from the rotation of the flywheel (e=MC2) is added to the
>torque
> > produced by the engine to help overcome the inertia of the vehicle and get
>it
> > moving. You can compensate for a reduction in that rotational inertia
>caused by
> > a reduction in mass, by simply raising the engine speed (a reduction in M
>can be
> > offset by a corresponding increase in C).<snip>
--
Marc Sayer
82 280ZXT
71 510 2.5 Trans Am vintage racer
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